document.write( "Question 1103833: A chemist has three different acid solutions. The first acid solution contains 15% acid, the second contains 30% acid, and the third contains 75% acid. He wants to use all three solutions to obtain a mixture of 216 liter containing 25% acid, using 2 times as much of the 75% solution as the 30% solution. How many liters of each solution should be used? \n" ); document.write( "
Algebra.Com's Answer #718529 by josgarithmetic(39618)\"\" \"About 
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x liters of 15%
\n" ); document.write( "y liters of 30%
\n" ); document.write( "z liters of 75%\r
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\n" ); document.write( "\n" ); document.write( "Accounting for pure acid
\n" ); document.write( "\"15x%2B30y%2B75z=%2825%29%28216%29\"
\n" ); document.write( "simplify to
\n" ); document.write( "\"3x%2B6y%2B15z=5%28216%29\"
\n" ); document.write( "\"x%2B2y%2B5z=360\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Accounting for total volume of blend
\n" ); document.write( "\"x%2By%2Bz=216\"\r
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\n" ); document.write( "\n" ); document.write( "---------------------------------------------------------------------------
\n" ); document.write( "He wants to use all three solutions to obtain a mixture of...,using 2 times as much of the 75% solution as the 30% solution.
\n" ); document.write( "---------------------------------------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "\"z%2Fy=2\"\r
\n" ); document.write( "\n" ); document.write( "\"z=2y\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Simplify this system: \"system%28x%2B2y%2B5%282y%29=360%2Cx%2By%2B2y=216%29\",...\r
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\n" ); document.write( "\n" ); document.write( "\"system%28x%2B12y=360%2Cx%2B3y=216%29\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B12y%29-%28x%2B3y%29=144\"\r
\n" ); document.write( "\n" ); document.write( "\"9y=144\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28y=16%29\"----------Use this to find z and x.
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