document.write( "Question 1103833: A chemist has three different acid solutions. The first acid solution contains 15% acid, the second contains 30% acid, and the third contains 75% acid. He wants to use all three solutions to obtain a mixture of 216 liter containing 25% acid, using 2 times as much of the 75% solution as the 30% solution. How many liters of each solution should be used? \n" ); document.write( "
Algebra.Com's Answer #718529 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! x liters of 15% \n" ); document.write( "y liters of 30% \n" ); document.write( "z liters of 75%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Accounting for pure acid \n" ); document.write( " \n" ); document.write( "simplify to \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Accounting for total volume of blend \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--------------------------------------------------------------------------- \n" ); document.write( "He wants to use all three solutions to obtain a mixture of...,using 2 times as much of the 75% solution as the 30% solution. \n" ); document.write( "---------------------------------------------------------------------------\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Simplify this system: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |