document.write( "Question 1103809: The amount of fill (weight of contents) put into a glass jar of spaghetti sauce is normally distributed with mean μ = 848 grams and standard deviation of σ = 15 grams.
\n" ); document.write( "(a) Describe the distribution of x, the amount of fill per jar.
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\n" ); document.write( "\n" ); document.write( "(b) Find the probability that one jar selected at random contains between 842 and 863 grams. (Give your answer correct to four decimal places.)
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\n" ); document.write( "(c) Describe the distribution of x, the mean weight for a sample of 27 such jars of sauce.
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\n" ); document.write( "\n" ); document.write( "(d) Find the mean of the x distribution. (Give your answer correct to the nearest whole number.)
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\n" ); document.write( "\n" ); document.write( "(ii) Find the standard error of the x distribution. (Give your answer correct to two decimal places.)
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\n" ); document.write( "\n" ); document.write( "(e) Find the probability that a random sample of 27 jars has a mean weight between 842 and 863 grams. (Give your answer correct to four decimal places.)
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Algebra.Com's Answer #718501 by Boreal(15235)\"\" \"About 
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This is presumably normally distributed.
\n" ); document.write( "z=(x-mean)/sd=(842-848)/15=-6/15=-0.4
\n" ); document.write( "z=(863-848)/15=+1
\n" ); document.write( "probability of z between those two numbers is 0.4968
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\n" ); document.write( "The next part is normally distributed (at least no reason given to suggest it isn't).
\n" ); document.write( "Mean is 848
\n" ); document.write( "The z values have the sd modified to be s/(sqrt(27)=2.89
\n" ); document.write( "Therefore, the z values will be between -6/2.89=-2.08 and 15/2.89=5.19
\n" ); document.write( "That probability is now 0.9812.
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