document.write( "Question 1103752: Solve the compound inequality. Express your answer using inequality signs, and then write your answer using interval notation. (If the solution set is empty, enter EMPTY or ∅.) 3y<5-2y<7+y \n" ); document.write( "
Algebra.Com's Answer #718475 by ikleyn(52799)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "This compound inequality\r\n" ); document.write( "\r\n" ); document.write( "3y < 5y-2 < 7+y \r\n" ); document.write( "\r\n" ); document.write( "is EQUIVALENT to (or, if you want, is, BY THE DEFINITION)\r\n" ); document.write( "\r\n" ); document.write( "the system of TWO INEQUALITIES\r\n" ); document.write( "\r\n" ); document.write( "3y < 5y-2 (1) and\r\n" ); document.write( "5y-2 < 7+y (2)\r\n" ); document.write( "\r\n" ); document.write( "in the sense that the final solution set is THE INTERSECTION of the solution sets for two inequalities (1) and (2).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "So, let us solve the inequality (1) first.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "1) 3y < 5y - 2 <=== is equivalent to (subtract 3y from both sides) ===> \r\n" ); document.write( "\r\n" ); document.write( " 0 < 2y - 2 <=== is equivalent to (add 2 to both sides) ===> \r\n" ); document.write( "\r\n" ); document.write( " 2 < 2y <=== is equivalent to (divide by 2 from both sides) ===>\r\n" ); document.write( "\r\n" ); document.write( " y > 1.\r\n" ); document.write( "\r\n" ); document.write( " So, the first inequality is solved, and its solution set is y > 1, or,\r\n" ); document.write( "\r\n" ); document.write( " in the interval notation, the set (1,infinity). (*)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Next, let us solve the second inequality \r\n" ); document.write( "\r\n" ); document.write( "2) 5 - 2y < 7 + y. <=== It is equivalent to (add 2y to both sides) ===>\r\n" ); document.write( "\r\n" ); document.write( " 5 < 7 + 3y <=== is equivalent to (subtract 7 from both sides) ===>\r\n" ); document.write( "\r\n" ); document.write( " -2 < 3y <=== is equivalent to (divide by 3 from both sides) ===>\r\n" ); document.write( "\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |