document.write( "Question 1103760: find the two solution sets for the following equation using the substitution method:\r
\n" ); document.write( "\n" ); document.write( "x+y=-3
\n" ); document.write( "(x+6)^2+(y+4)^2=37
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Algebra.Com's Answer #718456 by Fombitz(32388)\"\" \"About 
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\"x=-%28y%2B3%29\"
\n" ); document.write( "So then substituting,
\n" ); document.write( "\"%28-y-3%2B6%29%5E2%2B%28y%2B4%29%5E2=37\"
\n" ); document.write( "\"%28-y%2B3%29%5E2%2B%28y%2B4%29%5E2=37\"
\n" ); document.write( "\"y%5E2-6y%2B9%2By%5E2%2B8y%2B16=37\"
\n" ); document.write( "\"2y%5E2%2B2y-12=0\"
\n" ); document.write( "\"y%5E2%2By-6=0\"
\n" ); document.write( "\"%28y%2B3%29%28y-2%29=0\"
\n" ); document.write( "Two solutions:
\n" ); document.write( "\"y%2B3=0\"
\n" ); document.write( "\"y=-3\"
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\n" ); document.write( "\"y-2=0\"
\n" ); document.write( "\"y=2\"
\n" ); document.write( "Now use either equation to solve for x.
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