document.write( "Question 1103753: Find three consecutive even integers such that three times the second integer is six more than the sum of the first and third integers.
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Algebra.Com's Answer #718449 by josmiceli(19441) $\"\"$ $\"About$

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Let the consecutive even integers be:
\n" ); document.write( " $\"+n+\"$ , $\"+n+%2B+2+\"$ , and $\"+n%2B+4+\"$
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\n" ); document.write( " $\"+3%2A%28+n+%2B+2+%29+=+n+%2B+n+%2B+4+%2B+6+\"$
\n" ); document.write( " $\"+3n+%2B+6+=+2n+%2B+10+\"$
\n" ); document.write( " $\"+n+=+4+\"$
\n" ); document.write( "and
\n" ); document.write( " $\"+n+%2B+2+=+6+\"$
\n" ); document.write( " $\"+n+%2B+4+=+8+\"$
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\n" ); document.write( "The even integers are 4, 6, and 8
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\n" ); document.write( "check:
\n" ); document.write( " $\"+3%2A%28+n+%2B+2+%29+=+2n+%2B+10+\"$
\n" ); document.write( " $\"+3%2A6+=+8+%2B+10+\"$
\n" ); document.write( " $\"+18+=+18+\"$
\n" ); document.write( "OK\r
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