document.write( "Question 1103715: A piece of wire 64 cm long is cut into two pieces with different lengths. The two pieces are formed to TWO squares.
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document.write( " (a) Show that the combined area of the two squares A is given by A=2x^2-30x+256
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document.write( " (b) What is the minimum combined area of the two squares? \n" );
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Algebra.Com's Answer #718437 by math_helper(2461)![]() ![]() You can put this solution on YOUR website! A piece of wire 64 cm long is cut into two pieces with different lengths. The two pieces are formed to TWO squares. \n" ); document.write( " (a) Show that the combined area of the two squares A is given by A=2x^2-30x+256 \n" ); document.write( " (b) What is the minimum combined area of the two squares? \n" ); document.write( "===============================================================\r \n" ); document.write( "\n" ); document.write( "Let x = the length of the first piece \n" ); document.write( "the 64-x = the length of the 2nd piece\r \n" ); document.write( "\n" ); document.write( "Area of the first square is \n" ); document.write( "Aree of the 2nd square is \n" ); document.write( "\n" ); document.write( "Combined area = \n" ); document.write( "This simplifies to \n" ); document.write( "\n" ); document.write( "Notice that this disagrees with the value of A in the problem statement. I checked my work but I've been known to make errors. \n" ); document.write( "————————— \n" ); document.write( "To find the minimum, take the derivative. I will use my equation (the process is the same even if the correct equation is different): \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Take the derivative of A with respect to x: \n" ); document.write( " \n" ); document.write( "Set it to zero: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " Min Area = \n" ); document.write( "\n" ); document.write( "This is a local minimum of A because \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |