document.write( "Question 98709: HELP PLEASE!!! - Don't think I get it
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document.write( "write the frist 6 terms of the sequence:
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document.write( "1.an = n^3-1 (first n is subscript)
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document.write( "2.an = (n-1)^2 (first n is subscrpt)\r
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document.write( "Also- I need help with summation notation:
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document.write( "4+ 8+ +12+ 16 + 20 - write in summation notation
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document.write( "-7-8-9-10-11 in summation
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document.write( "5/6+6/7+7/8+8/9+... summation notation\r
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document.write( "Thanks so very much
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Algebra.Com's Answer #71841 by Adam(64)![]() ![]() ![]() You can put this solution on YOUR website! Sequence is just some (ordered) list of numbers(terms).The equation \n" ); document.write( "1st : \n" ); document.write( "2nd : \n" ); document.write( "3rd : \n" ); document.write( "and so on...\r \n" ); document.write( "\n" ); document.write( "Summation- you are just summing terms of sequence. For instance, if you have : \n" ); document.write( " \n" ); document.write( " , same like in the first problem, !but summed! So not 0 , 7 , 25 , 63 , but 0+7+25+63 = 95.(You are substituting through n=1 to n=6 and summing together.\r \n" ); document.write( "\n" ); document.write( "or \n" ); document.write( "given 4+8+12+16+20 you can rewrite as \n" ); document.write( "-7-8-9-10-10-11 as \n" ); document.write( "and finally 5/6+6/7+7/8+8/9+... as \n" ); document.write( " \n" ); document.write( "-method of rewriting into summation notation is always based on some preliminary thought, as multiples of 4 etc.. so go through it and give some thought about it... \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |