document.write( "Question 1103663: the length of a rectangle is 10ft less than twice the width. if the perimeter is 178 ft, find the length and width. \n" ); document.write( "

Algebra.Com's Answer #718361 by ikleyn(52787) $\"\"$ $\"About$

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document.write( "(1)    L = 2W-10\r\n" );
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document.write( "(2)    L +      W +  L     + W = 178\r\n" );
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document.write( "      (2W-10) + W + (2W-10) + W = 178  ====>\r\n" );
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document.write( "      6W - 20 = 178  ====>  6W = 178 + 20 = 198  ====>  W =  = 33.\r\n" );
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document.write( "Amswer.  W = 33 ft,  L = 2W-10 = 2*33-10 = 56 ft.\r\n" );
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