document.write( "Question 1103635: Find the length and width of a rectangle whose perimeter is 32 feet and whose area is 55 square feet \n" ); document.write( "
Algebra.Com's Answer #718332 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
\"system%282x%2B2y=32%2Cxy=55%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"system%28x%2By=16%2Cxy=55%29\"\r
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\n" ); document.write( "\n" ); document.write( "Any simple possibilities?
\n" ); document.write( "11 and 5 ?
\n" ); document.write( "Just the factorization for 55.
\n" ); document.write( "This combination works.
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\n" ); document.write( "Length, 11
\n" ); document.write( "Width, 5.
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\n" ); document.write( "\n" ); document.write( "Do you want Algebra instead?\r
\n" ); document.write( "\n" ); document.write( "\"y=16-x\"
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\n" ); document.write( "\"x%2816-x%29=55\"
\n" ); document.write( "\"-x%5E2%2B16x=55\"
\n" ); document.write( "\"-x%5E2%2B16x-55=0\"
\n" ); document.write( "\"x%5E2-16x%2B55=0\"------and use either general solution or factoring.
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