document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1103616>Question 1103616</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A photo measures 10cm by 8cm. The photo is cropped by cutting a strip of a constant width of the top and one side of the photo. If the new area of the new photo is reduced to 62.5% of the original area, find the width of the cut and the new dimensions of the cropped photo. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #718308 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=718308\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area is 80 cm^2=10 x 8<BR>\n" );
document.write( "Need to reduce it to 5/8 (62.5%) of original area, which is 50 cm^2.\r<BR>\n" );
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document.write( "The amount removed is x and that is 2x from each the 10 and the 8.<BR>\n" );
document.write( "(10-2x)^2(8-2x)^2=50<BR>\n" );
document.write( "80-36x+4x^2=50<BR>\n" );
document.write( "4x^2-36x+30=0<BR>\n" );
document.write( "2x^2-18x+15=0<BR>\n" );
document.write( "x=(1/4)(18+/-sqrt(324-120))<BR>\n" );
document.write( " x=(1/4)(18+ sqrt (204))=8.07, doesn't make sense.  Other root is <BR>\n" );
document.write( "x=(1/4)(18-sqrt (204))=0.93 cm  one ANSWER<BR>\n" );
document.write( "The new dimensions are 10-1.86=8.14 cm x 8-1.86=6.14 cm other ANSWER<BR>\n" );
document.write( "That product is 49.98 cm^2, close enough with rounding error. </SPAN>\n" );
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