document.write( "Question 1103620: An aircraft flew 4 hours with the wind. The return trip took 5 hours against the wind. If the speed of the plane in still air is 184 miles per hour more than the speed of the​ wind, find the wind speed and the speed of the plane in still air. \n" ); document.write( "
Algebra.Com's Answer #718304 by ikleyn(52750)\"\" \"About 
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\n" ); document.write( "An aircraft flew 4 hours with the wind. The return trip took 5 hours against the wind. If the speed of the plane in still air
\n" ); document.write( "is 184 miles per hour more than the speed of the​ wind, find the wind speed and the speed of the plane in still air.
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\n" ); document.write( "\n" ); document.write( "        In such/(in similar) problems the term \"in still water\" is commonly accepted;\r
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\n" ); document.write( "\n" ); document.write( "        but the term \"in still air\" is NEVER used.\r
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\n" ); document.write( "\n" ); document.write( "        Instead, the term \"at no wind\" is used.\r
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document.write( "Let  \"u\"  be the aircraft speed at no wind (in miles per hour),  and\r\n" );
document.write( "let  \"v\"  be speed of the wind.\r\n" );
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document.write( "Then the aircraft tailwind speed is (u+v) mph,\r\n" );
document.write( "while the aircraft speed against the wind is (u-v) mph, which is exactly 184 mph.\r\n" );
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document.write( "Therefore, the one-way distance aircraft covered flying against the wind was \r\n" );
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document.write( "184*5 = 920 miles.\r\n" );
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document.write( "Hence, flying tailwind, the aircraft tailwind speed was  u+v = \"920%2F4\" = 230 mph.\r\n" );
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document.write( "Now you have these two equations\r\n" );
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document.write( "u + v = 230,    (1)\r\n" );
document.write( "u - v = 184.    (2)     (given).\r\n" );
document.write( "----------------------------------------Add the equations (both sides). You will get\r\n" );
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document.write( "2u = 230 + 184 = 414  ====>  u = \"414%2F2\" = 207.\r\n" );
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document.write( "Then from eq(1),  v = 230 - 207 = 23.\r\n" );
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document.write( "Answer.  The aircraft speed at no wind is  207 mph.   The speed of the wind is  23 mph.\r\n" );
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\n" ); document.write( "It is a typical \"tailwind and headwind\" word problem.\r
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\n" ); document.write( "\n" ); document.write( "See the lessons \r
\n" ); document.write( "\n" ); document.write( "    - Wind and Current problems \r
\n" ); document.write( "\n" ); document.write( "    - Wind and Current problems solvable by quadratic equations \r
\n" ); document.write( "\n" ); document.write( "    - Selected problems from the archive on a plane flying with and against the wind \r
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\n" ); document.write( "\n" ); document.write( "In these lessons you will find the detailed solutions of many similar problems. \r
\n" ); document.write( "\n" ); document.write( "Consider them as samples.  Read them attentively.\r
\n" ); document.write( "\n" ); document.write( "In this way you will learn how to solve similar problems once and for all.\r
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\n" ); document.write( "\n" ); document.write( "Also,  you have this free of charge online textbook in ALGEBRA-I in this site\r
\n" ); document.write( "\n" ); document.write( "    ALGEBRA-I - YOUR ONLINE TEXTBOOK.\r
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\n" ); document.write( "\n" ); document.write( "The referred lessons are the part of this textbook under the section \"Word problems\",  the topic \"Travel and Distance problems\".\r
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\n" ); document.write( "\n" ); document.write( "Save the link to this online textbook together with its description\r
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\n" ); document.write( "\n" ); document.write( "Free of charge online textbook in ALGEBRA-I
\n" ); document.write( "https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson\r
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\n" ); document.write( "\n" ); document.write( "to your archive and use it when it is needed.\r
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