document.write( "Question 1103369: Determine if the limit exists as n goes to infinity:\r
\n" ); document.write( "\n" ); document.write( "\"+1%2F%28n%2B1%29%2B1%2F%28n%2B2%29\" +...+ \"1%2F%282n-1%29+%2B+1%2F%282n%29\".\r
\n" ); document.write( "\n" ); document.write( "If the limit exists then find its value.
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Algebra.Com's Answer #718183 by math_helper(2461)\"\" \"About 
You can put this solution on YOUR website!
Let \"+S%5Bn%5D+=+1%2F%28n%2B1%29+%2B+1%2F%28n%2B2%29+\" + … + \"+1%2F%282n-1%29+%2B+1%2F2n+\"\r
\n" ); document.write( "\n" ); document.write( "Consider \"+nS%5Bn%5D+=+n%2F%28n%2B1%29+%2B+n%2F%28n%2B2%29+\" + … + \"+n%2F%282n-1%29+%2B+n%2F2n+\"
\n" ); document.write( "For \"+n%3E=1+\":
\n" ); document.write( "\"+n%2F%28n%2B1%29+%3C+1+\"
\n" ); document.write( "\"+n%2F%28n%2B2%29+%3C+1+\"
\n" ); document.write( ": :
\n" ); document.write( "\"+n%2F%282n%29+%3C+1+\"\r
\n" ); document.write( "\n" ); document.write( "That's n terms, each of which is less than 1.
\n" ); document.write( " \"+nS%5Bn%5D+%3C+n+\"
\n" ); document.write( "which implies
\n" ); document.write( " \"+S%5Bn%5D+%3C+1+\" \r
\n" ); document.write( "\n" ); document.write( "For the lower bound: \"+nS%5Bn%5D+%3E=+n%2F2+\" (all but the last term are > n/2)
\n" ); document.write( " \"+S%5Bn%5D+%3E+1%2F2+\"\r
\n" ); document.write( "\n" ); document.write( "So \"+1%2F2+%3C+S%5Bn%5D+%3C+1+\" and the series has a limit as \"+n+\" —> \"+infinity+\" .
\n" ); document.write( "———————————
\n" ); document.write( "To find the limit value, I cheated and used a one-line Perl script:
\n" ); document.write( "perl -e '$m=10000000; for($i=$m, $s=0; $i<(2*$m); $i++) { $s += 1/($i+1); } print \"$s\n\";'
\n" ); document.write( "0.693147155559907
\n" ); document.write( "perl -e '$m=100000000; for($i=$m, $s=0; $i<(2*$m); $i++) { $s += 1/($i+1); } print \"$s\n\";'
\n" ); document.write( "0.693147178059741\r
\n" ); document.write( "\n" ); document.write( "Which looks like ln(2). \r
\n" ); document.write( "\n" ); document.write( "————————————
\n" ); document.write( "EDIT: I also should have shown that the series terms get smaller as \"+n+\" —> \"+infinity+\"
\n" ); document.write( "\"+S%5Bn%5D+-+S%5Bn-1%5D+=+1%2F%282n%2A%282n-1%29%29++\" which goes to 0 monotonically as \"+n\" —> \"+infinity+\". This means \"+S%5Bn%5D+\" increases by smaller amounts as n increases, and the series converges.
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