document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=98685>Question 98685</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A Gardener has 60 feet of fencing to enclose a rectangular garden and the two foot wide border surrounding it.\r<BR>\n" );
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document.write( "If The length of the garden is twice its width, what are its dimensions? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #71816 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=71816\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> GARDEN SIDES=X&2X<BR>\n" );
document.write( "GARDEN PLUS BORDER=(X+4)&(2X+4)<BR>\n" );
document.write( "PERIMETER=2(X+4)+2(2X+4)=60<BR>\n" );
document.write( "P=2X+8+4X+8=60<BR>\n" );
document.write( "P=6X+16=60<BR>\n" );
document.write( "6X=60-16<BR>\n" );
document.write( "6X=44<BR>\n" );
document.write( "X=44/6<BR>\n" );
document.write( "X=7.33 LENGTH OF THE GARDEN<BR>\n" );
document.write( "2*7.33=14.66 WIDTH OF THE GARDEN.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "2(7.33+4)+2(14.67+4)=60<BR>\n" );
document.write( "2*11.33+2*18.67=60<BR>\n" );
document.write( "22.66+37.24=60<BR>\n" );
document.write( "60=60 <BR>\n" );
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