document.write( "Question 1103434: in how many ways can five couples be seated in a row if
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Algebra.Com's Answer #718159 by ikleyn(52778)\"\" \"About 
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document.write( "a.  there are no restrictions?                             10! = 10*9*8*7*6*5*4*3*2*1 = 3628800 ways.\r\n" );
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document.write( "b.  each couple must be seated together?                   \"5%21%2A2%5E5\" = 120*32 = 3840 ways  (120 permutations for 5 objects, each of which can be in one \r\n" );
document.write( "                                                          of the two states: (h,w)  or (w,h),  where \"h\" stands for husband and \"w\" stands for wife.\r\n" );
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document.write( "c.  each husband must be seated to the left of his wife?   5! = 5*4*3*2*1 = 120 ways.\r\n" );
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