document.write( "Question 1103454: opqrs is a right pyramid whose base is a square of sides 12cm each. given that the slant height of the pyramid is 15 cm. find,
\n" ); document.write( "a)height of the pyramid
\n" ); document.write( "b)the volume of the pyramid
\n" ); document.write( "c)the total surface area of the pyramid
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Algebra.Com's Answer #718151 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The side of the base is 12; so the distance across the base from one side to the other is 12; so the distance from the middle of one side of the base to the center of the base is 6.

\n" ); document.write( "Then with a slant height of 15, the height of the pyramid is the other leg of a right triangle with hypotenuse 15 and one leg 6:
\n" ); document.write( "\"sqrt%2815%5E2-6%5E2%29+=+sqrt%28225-36%29+=+sqrt%28189%29+=+3%2Asqrt%2821%29\"

\n" ); document.write( "Answer a: \"3%2Asqrt%2821%29\" (cm)

\n" ); document.write( "The volume of the pyramid is \"%281%2F3%29Bh+=+%281%2F3%29%28144%29%283%2Asqrt%2821%29%29+=+144%2Asqrt%2821%29\"
\n" ); document.write( "Answer b: \"144%2Asqrt%2821%29\" (cubic cm)

\n" ); document.write( "The area of the base is 144; the area of each triangular face is \"%281%2F2%29bh+=+%281%2F2%29%2812%29%2815%29+=+90\"
\n" ); document.write( "The total surface area is \"144%2B4%2890%29+=+144%2B360+=+504\" (square cm)
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