document.write( "Question 1103409: \r
\n" );
document.write( "\n" );
document.write( "Thanks guys! \n" );
document.write( "
Algebra.Com's Answer #718097 by algebrahouse.com(1659)![]() ![]() You can put this solution on YOUR website! 6x² + x = 40 \n" ); document.write( "6x² + x - 40 = 0 \n" ); document.write( "6x² + 16x - 15x - 40 = 0 {split x into 16x and -15x, they multiply to get 6(-40) and add to get 1} \n" ); document.write( "2x(3x + 8) - 5(3x + 8) = 0 {factored 2x out of first two terms and -5 out of last two terms} \n" ); document.write( "(3x + 8)(2x - 5) = 0 {factored out the common factor, (3x + 8)} \n" ); document.write( "3x + 8 = 0 or 2x - 5 = 0 {set each factor equal to zero} \n" ); document.write( "3x = -8 or 2x = 5 {subtracted 8 and added 5} \n" ); document.write( "x = -8/3 or x = 5/2 {divided by 3 and divided by 2} \n" ); document.write( " For more help like this, visit: www.algebrahouse.com \n" ); document.write( " |