document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1103381>Question 1103381</A>: <I><SPAN STYLE=\"word-break: break-all;\"> IF DON INVESTS $6000 AT 9% INTREST COMPOUNDED QUATERLY, FIND THE AMOUNT AFTER 7 YEARS </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #718088 by </B><A HREF=/tutors/aboutme.mpl?userid=snoreaylil><B>snoreaylil(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=snoreaylil><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=718088\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> to solve you'll first need your equation which would be y=6000(1.09)^x <BR>\n" );
document.write( "then you find what 4x7 is because quarterly is 4 times a year 4x7=28<BR>\n" );
document.write( "you plug 28 in for x so now your equation is y=6000(1.09)^28<BR>\n" );
document.write( "y=6000(11.167)<BR>\n" );
document.write( "y=67,002<BR>\n" );
document.write( "Don will have $67,002 after 7 years </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );