document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1103290>Question 1103290</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Paul invests &#8203;$3000 in a savings account earning interest at a rate of <BR>\n" );
document.write( "4&#8203;% compounded annually. How long will it take for the &#8203;$3000 to grow to &#8203;$<BR>\n" );
document.write( "5700?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #718087 by </B><A HREF=/tutors/aboutme.mpl?userid=snoreaylil><B>snoreaylil(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=snoreaylil><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=718087\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> first you must make an equation. In this case it would be y=3000(1+.04)^x<BR>\n" );
document.write( "then you can make a table with said equation<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/display-illustration.mpl?tutor=snoreaylil&illustration_name=unnamed.jpg\"><BR>\n" );
document.write( "you scroll down the table until you find the number 5700 or something close to it<BR>\n" );
document.write( "and then the value of x is your amount of years <BR>\n" );
document.write( "in this case x=17 <BR>\n" );
document.write( "It will take 17 years for the $3000 to turn into 5700 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );