document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1103327>Question 1103327</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 50-foot ladder is placed at a 60-degree angle of elevation from the ground. The ladder terminates at the top of a building.\r<BR>\n" );
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document.write( "Sketch the situation and label each side of the triangle. H = height of the building,	<BR>\n" );
document.write( "L= length of ladder, D = distance	between	the	bottom of the	ladder and the bottom	<BR>\n" );
document.write( "of the building. Identify	which angle is the angle of elevation.\r<BR>\n" );
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document.write( "Use a trig function to calculate the distance between the bottom of the ladder	<BR>\n" );
document.write( "and the bottom of the building.\r<BR>\n" );
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document.write( "Use a trig function to calculate the height of the tower. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #718080 by </B><A HREF=/tutors/aboutme.mpl?userid=diana_granger><B>diana_granger(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=diana_granger><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=diana_granger><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=718080\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> By the 30-60-90 triangle,<BR>\n" );
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document.write( "L=2a<BR>\n" );
document.write( "H=a sq root of 3<BR>\n" );
document.write( "D=a\r<BR>\n" );
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document.write( "By the given, L=2a=50<BR>\n" );
document.write( "So a=25\r<BR>\n" );
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document.write( "H=25(sq root of 3) </SPAN>\n" );
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