document.write( "Question 98661: A hose can fill a swimming pool in 6 hours. Another hose needs 3 more hours to fill the pool than the two hoses combined. How long would it take the second hose to fill the pool? \n" ); document.write( "
Algebra.Com's Answer #71808 by malakumar_kos@yahoo.com(315)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( " A hose can fill a swimming pool in 6 hours. Another hose needs 3 more hours to fill the pool than the two hoses combined. How long would it take the second hose to fill the pool? \r
\n" ); document.write( "\n" ); document.write( " Time taken by horse A to fill the pool = 6 hrs\r
\n" ); document.write( "\n" ); document.write( " Time taken by horse B to fill the pool = y hrs\r
\n" ); document.write( "\n" ); document.write( " Time taken by both together to fill the pool = x hrs\r
\n" ); document.write( "\n" ); document.write( " therefore y = x+3........(1)\r
\n" ); document.write( "\n" ); document.write( " qn'ty filled by horse A in 1 hr = 1/6\r
\n" ); document.write( "\n" ); document.write( " qn'ty filled by horse B in 1 hr = 1/y
\n" ); document.write( " qn'ty filled by both in 1 hr = 1/x\r
\n" ); document.write( "\n" ); document.write( " therefore 1/x = 1/6+1/y........(2)\r
\n" ); document.write( "\n" ); document.write( " substituting for y in eq'n (2) we get\r
\n" ); document.write( "\n" ); document.write( " 1/x = 1/6+1/(x+3)\r
\n" ); document.write( "\n" ); document.write( " 1/x = x+3+6/6(x+3)\r
\n" ); document.write( "\n" ); document.write( " 1/x = x+9/6(x+3)\r
\n" ); document.write( "\n" ); document.write( " 6(x+3) = x(x+9)\r
\n" ); document.write( "\n" ); document.write( " 6x+18 = x^2+9x\r
\n" ); document.write( "\n" ); document.write( " x^2+9x-6x-18 = 0
\n" ); document.write( " x^2+3x-18 = 0\r
\n" ); document.write( "\n" ); document.write( " x^2+6x-3x-18 = 0\r
\n" ); document.write( "\n" ); document.write( " x(x+6)-3(x+6)= 0\r
\n" ); document.write( "\n" ); document.write( " (x+6)(x-3)= 0\r
\n" ); document.write( "\n" ); document.write( " substituting for x in eq'n (1) we get y = x+3\r
\n" ); document.write( "\n" ); document.write( " x-3 = 0 or x = 3 therefore y = 3+3 = 6\r
\n" ); document.write( "\n" ); document.write( " Horse B would take 6 hrs to fil the pool
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