document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1103340>Question 1103340</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 50-foot ladder is placed at a 60-degree angle of elevation from the ground. The ladder terminates at the top of a building.\r<BR>\n" );
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document.write( "a. Sketch the situation and label each side of the triangle. H = height of the building,    <BR>\n" );
document.write( "L= length of ladder, D = distance between the bottom of the ladder and the bottom of the building. Identify which angle is the angle of elevation.\r<BR>\n" );
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document.write( "b. Use a trig function to calculate the distance between the bottom of the ladder    <BR>\n" );
document.write( "and the bottom of the building.\r<BR>\n" );
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document.write( "c. Use a trig function to calculate the height of the tower. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #718063 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=718063\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> yuur diagram will look something like this:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" src = \"http://theo.x10hosting.com/2017/120201.jpg\" alt=\"$$$\">\r<BR>\n" );
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document.write( "your angle of elevation is 60 degrees.\r<BR>\n" );
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document.write( "sin(60) = opposite / hypotenuse = H/L.\r<BR>\n" );
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document.write( "cos(60) = adjacent / hypotenuse = D/L.\r<BR>\n" );
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document.write( "since L = 50 (length of the ladder), then:\r<BR>\n" );
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document.write( "sin(60) = H/50.\r<BR>\n" );
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document.write( "cos(60) = D/50.\r<BR>\n" );
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document.write( "solve for H to get H = 50 * sin(60).\r<BR>\n" );
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document.write( "solve for D to get D = 50 * cos(60).\r<BR>\n" );
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document.write( "you will get H = 43.30127019\r<BR>\n" );
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document.write( "you will get D = 25\r<BR>\n" );
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document.write( "since you have a right triangle with a hypotenuse of L and two lets of H and D, then, by pythagorus, you should get L^2 = H^2 + D^2.\r<BR>\n" );
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document.write( "this becomes 50^2 = 43.30127019^2 + 25^2\r<BR>\n" );
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document.write( "solve to get 2500 = 1875 + 625 which becomes 2500 = 2500, confirming that the solution is correct.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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