document.write( "Question 98506: y1=1/x+3, y2=1/x, and y1+y2=1/15
\n" ); document.write( "Find all the values of x \n" ); document.write( "

Algebra.Com's Answer #71806 by malakumar_kos@yahoo.com(315) $\"\"$ $\"About$

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y1=1/x+3, y2=1/x, and y1+y2=1/15
\n" ); document.write( "Find all the values of x\r
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\n" ); document.write( "\n" ); document.write( " 1/(x+3)+1/(x) = 1/15\r
\n" ); document.write( "\n" ); document.write( " x+x+3/x(x+3)= 1/15\r
\n" ); document.write( "\n" ); document.write( " 15(2x+3)= x(x+3)\r
\n" ); document.write( "\n" ); document.write( " 30x+45 = x^2+3x\r
\n" ); document.write( "\n" ); document.write( " x^2+3x-30x-45 = 0\r
\n" ); document.write( "\n" ); document.write( " x^2-27x-45 = 0\r
\n" ); document.write( "\n" ); document.write( " $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$ \r
\n" ); document.write( "\n" ); document.write( " x = 27 +- sqrt (27^2+180)/2
\n" ); document.write( " simplify to get the value of x
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