document.write( "Question 1103350: The drama club is spending $224 to put on a play. They plan to sell tickets at $3.00 each. If they sell n tickets, which of the following represents their profit after expenses? \n" ); document.write( "
Algebra.Com's Answer #718054 by Theo(13342)\"\" \"About 
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they spent 224.
\n" ); document.write( "they sell tickets at 3 dollars apiece.
\n" ); document.write( "n is the number of tickets.\r
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\n" ); document.write( "\n" ); document.write( "profit = revenue - expenses.\r
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\n" ); document.write( "\n" ); document.write( "revenue = 3 * n
\n" ); document.write( "expenses = 224.
\n" ); document.write( "profit = p\r
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\n" ); document.write( "\n" ); document.write( "your equation is p = 3 * n - 224.\r
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\n" ); document.write( "\n" ); document.write( "replace p with whatever variable you use to represent profit and you should be ok.\r
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\n" ); document.write( "\n" ); document.write( "they will start to make a profit after they sell about 75 tickets.
\n" ); document.write( "thaat's their break even point.\r
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\n" ); document.write( "\n" ); document.write( "you solve for that by setting p = 0.\r
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\n" ); document.write( "\n" ); document.write( "when p = 0, the equation becomes 0 = 3 *n -224
\n" ); document.write( "add 224 to both sides of this equation to get 224 = 3 * n
\n" ); document.write( "divide both sides of this equation by 3 to get 224 / 3 = n
\n" ); document.write( "solve for n to get n = 224/3 = 74.67 rounded to 2 decimal places.\r
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\n" ); document.write( "\n" ); document.write( "when they sell 74 tickets, they still haven't made a profit.
\n" ); document.write( "when they sell 75 tickets or more, they are in the green.\r
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