document.write( "Question 1103354: Rover was 5 years older than Yolanda. In 10 years he found that 4 times his age exceede twice Yolanda's age by only 50. How old were Rover and Yolanda in the beginning? I tried to solve this, but my answers wouldn't solve. Could you help me learn how? Thank you! \n" ); document.write( "
Algebra.Com's Answer #718050 by greenestamps(13206)\"\" \"About 
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\n" ); document.write( "My thought for setting up this problem was to use the ages after the 10 years to set up the problem. Rover will always be 5 years older the Yolanda, so

\n" ); document.write( "let x = Yolanda's age after the 10 years
\n" ); document.write( "then x+5 is Rover's age then

\n" ); document.write( "The problem says 4 times Rover's age at this time is 50 more than twice Yolanda's age:
\n" ); document.write( "\"4%28x%2B5%29+=+2%28x%29%2B50\"
\n" ); document.write( "\"4x%2B20+=+2x%2B50\"
\n" ); document.write( "\"2x+=+30\"
\n" ); document.write( "\"x+=+15\"

\n" ); document.write( "Yolanda's age after the 10 years is 15, so her age at the beginning was 5; that means Rover's age at the beginning was 10.
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