document.write( "Question 1103287: Troy and Toledo are 64 mi apart. A bus left Troy to Toledo at an average speed of 84 mph. At the same time, a car left Toledo to troy. The two vehicles passed each other 20 minutes after they started. What was the average speed of the car?
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Algebra.Com's Answer #718004 by richwmiller(17219)\"\" \"About 
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Troy and Toledo are 64 mi apart. A bus left Troy to Toledo at an average speed of 84 mph. At the same time, a car left Toledo to troy. The two vehicles passed each other 20 minutes after they started. What was the average speed of the car?
\n" ); document.write( "1/3*84 mph=28 miles for the bus\r
\n" ); document.write( "\n" ); document.write( "64-28=36 miles for the car\r
\n" ); document.write( "\n" ); document.write( "r*t=d
\n" ); document.write( "r*1/3=36
\n" ); document.write( "r/3=36
\n" ); document.write( "r=36*3=108 mph
\n" ); document.write( "Those are absurd speeds. Busses don't travel that fast and cars attempting to go that fast end up in accidents.\r
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