document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1103276>Question 1103276</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 25,000 dollars is invested at an interest rate of 9 percent per year, find the value of the investment at the end of 5 years<BR>\n" );
document.write( "(a) Annual $______<BR>\n" );
document.write( "(b) Semiannual$_____ <BR>\n" );
document.write( "(c) Daily$______<BR>\n" );
document.write( "(d) Continuously $_______ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #717982 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=717982\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Compound interest formula<BR>\n" );
document.write( "P=Po(1+r/n)^nt<BR>\n" );
document.write( "Po=25000<BR>\n" );
document.write( "r=0.09<BR>\n" );
document.write( "t=5<BR>\n" );
document.write( "n=1 for annual  25000(1+.09)^5=$38465.60<BR>\n" );
document.write( "2 for semi annual 25000(1.045)^10=$38824.24<BR>\n" );
document.write( "365 for daily $39205.63<BR>\n" );
document.write( "P=Poe^rt for continuous compounding. $39207.80 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );