document.write( "Question 98655: Please tell me if I did the following problem correctly:\r
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document.write( "If y varies inversely as x and y=3, when x=6. Find y when x=36.\r
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document.write( "This is what I came up with:\r
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document.write( "3/36=y/6
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document.write( "36*y=36y
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document.write( "3*6=18
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document.write( "18/36=1/2\r
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document.write( "So when x=36, y=1/2.\r
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document.write( "Thank you for your input.
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Algebra.Com's Answer #71797 by malakumar_kos@yahoo.com(315)![]() ![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( " If y varies inversely as x and y=3, when x=6. Find y when x=36. \r \n" ); document.write( "\n" ); document.write( " y varies inversely as x or y = k/x \n" ); document.write( " k = xy where k is a proportionality \r \n" ); document.write( "\n" ); document.write( " constant\r \n" ); document.write( "\n" ); document.write( " when x= 6 y =3 k = 6.3 = 18 \n" ); document.write( " \n" ); document.write( " when x = 36 y = k/36 = 18/36 = 1/2 \n" ); document.write( " |