document.write( "Question 98653: Find the dimensions of a rectangle whose area is 180cm^2 and whose perimeter is 54 cm. \n" ); document.write( "
Algebra.Com's Answer #71794 by praseenakos@yahoo.com(507)\"\" \"About 
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Question:\r
\n" ); document.write( "\n" ); document.write( "Find the dimensions of a rectangle whose area is 180cm^2 and whose perimeter is 54 cm.\r
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\n" ); document.write( "\n" ); document.write( "Given that, \r
\n" ); document.write( "\n" ); document.write( "\"Area+=+180+cm%5E2+\" and \r
\n" ); document.write( "\n" ); document.write( "\"+perimeter+=+54+cm+\"\r
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\n" ); document.write( "\n" ); document.write( "Perimeter of rectangle is given by the formula, 2( length + width)\r
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\n" ); document.write( "\n" ); document.write( "==> 2( length + width) = 54\r
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\n" ); document.write( "\n" ); document.write( "==> ( length + width) = \"+54%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "==> ( length + width) = 27\r
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\n" ); document.write( "\n" ); document.write( "Now suppose, length = x cm\r
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\n" ); document.write( "\n" ); document.write( "Then width = 27 - x \r
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\n" ); document.write( "\n" ); document.write( "Now area is given by the formula, length * width\r
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\n" ); document.write( "\n" ); document.write( "That is length * width = 180 cm^2\r
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\n" ); document.write( "\n" ); document.write( "==> x * ( 27-x) = 180\r
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\n" ); document.write( "\n" ); document.write( "==> \"+27x+-+x%5E2+=+180+\"\r
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\n" ); document.write( "\n" ); document.write( "==> \"+x%5E2+-+27+x+%2B+180+=+0+\" -----------------(1) \r
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\n" ); document.write( "\n" ); document.write( "This is a quadratic equation and you can solve this equation using quadratic formula for x.\r
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\n" ); document.write( "\n" ); document.write( "==> \"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Comparing equation(1) with the standard quadratic equation,
\n" ); document.write( "\"ax%5E2+%2B+bx+%2B+c+=+0\", we have,\r
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\n" ); document.write( "\n" ); document.write( "a = 1, b = -27 and c = 180\r
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\n" ); document.write( "\n" ); document.write( "==> \"x+=+%28-%28-27%29+%2B-+sqrt%28%28-27%29%5E2-4%2A1%2A180+%29%29%2F%282%2A1%29+\"\r
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\n" ); document.write( "\n" ); document.write( "==> \"x+=+%28+27+%2B-+sqrt%28729-720%29%29+%2F+2++\"\r
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\n" ); document.write( "\n" ); document.write( "==> \"x+=+%28+27+%2B-+sqrt+9+%29+%2F2++\"\r
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\n" ); document.write( "\n" ); document.write( "==> \"x+=+%28+27+%2B+-+3%29%2F2+\"\r
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\n" ); document.write( "\n" ); document.write( "==> either, \"+x+=+%2827+%2B+3%29%2F2\" or \"+x+=+%2827+-+3%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "==> either, \"+x+=+30+%2F2\" or \"+x+=+24%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "==> either, \"+x+=+15\" or \"+x+=+12\"\r
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\n" ); document.write( "\n" ); document.write( "that is either length = 15 cm of 12 cm\r
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\n" ); document.write( "\n" ); document.write( "When length = 15 cm, width = 27 - 15 = 12 cm\r
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\n" ); document.write( "\n" ); document.write( "And when length = 12cm, width = 27 - 12 = 15 cm.\r
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\n" ); document.write( "\n" ); document.write( "Hence the solution.\r
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\n" ); document.write( "\n" ); document.write( "Hope you found the explanation useful.\r
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\n" ); document.write( "\n" ); document.write( "Regards.\r
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\n" ); document.write( "\n" ); document.write( "Praseena.\r
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