document.write( "Question 98656: Please I could really use your help. I'm lost. Here is the question.
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document.write( "Write an equation of a line in standard form given these two points.
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document.write( "(2/3,-1/4) and (5/9, -13/15). I am so confused. This question is from
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document.write( "my teacher. \n" );
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Algebra.Com's Answer #71793 by malakumar_kos@yahoo.com(315)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " Write an equation of a line in standard form given these two points. \n" ); document.write( "(2/3,-1/4) and (5/9, -13/15)\r \n" ); document.write( "\n" ); document.write( " ( x1,y1) = (2/3,-1/4) (x2,y2) = (5/9,-13/15)\r \n" ); document.write( "\n" ); document.write( " x2-x1/x-x1 = y2-y1/y-y1\r \n" ); document.write( "\n" ); document.write( " (5/9-2/3)/(x-2/3) = (-13/15+1/4)/(y+1/4)\r \n" ); document.write( "\n" ); document.write( " ( 15-2/9)/(3x-2)/3 = [(-52+15)/60]/4y+1/4\r \n" ); document.write( "\n" ); document.write( " 13(3)/9(3x-2) = -37/60/4y+1/4\r \n" ); document.write( "\n" ); document.write( " 13/3(3x-2) = -37(4)/60(4y+1)\r \n" ); document.write( "\n" ); document.write( " 13/3(3x-2) = -37/15(4y+1)\r \n" ); document.write( "\n" ); document.write( " 13 .5(4y+1) = -37(3x-2)\r \n" ); document.write( "\n" ); document.write( " 65(4y+1) = -111x+74 \n" ); document.write( " 111x + 260y+65-74 = 0 \n" ); document.write( " 111x +260y -9 = 0 is the required eq'n \n" ); document.write( " |