document.write( "Question 98491: Please help me with this. Here is the Problem.\r
\n" ); document.write( "\n" ); document.write( "Find the vertex, focus, and directrix of the parabola given by:\r
\n" ); document.write( "\n" ); document.write( " x^2-10x-8y+33=0\r
\n" ); document.write( "\n" ); document.write( "I tried completing the square first, but I couldn't finish it. I couldn't figure out what to do with the 33. Please help me if you can. Thanks in advance.
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Algebra.Com's Answer #71787 by scott8148(6628)\"\" \"About 
You can put this solution on YOUR website!
this is from Wikipedia - \"In Cartesian coordinates, a parabola with an axis parallel to the y axis with vertex (h, k), focus (h, k + p), and directrix y = k - p, with p being the distance from the vertex to the focus, has the equation (x-h)^2=4p(y-k)\"\r
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\n" ); document.write( "\n" ); document.write( "x^2-10x-8y+33=0 ... x^2-10x+25-8y+8=0 ... x^2-10x+25=8y-8 ... (x-5)^2=4(2)(y-1)\r
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\n" ); document.write( "\n" ); document.write( "so vertex is (5,1), focus is (5,3), and directrix is y=-1
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