document.write( "Question 1103173: find the area of the triangle whose vertices are (1/3,8/3), (5/4, 1/4)and (67,-13/6) \n" ); document.write( "
Algebra.Com's Answer #717861 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! find the area of the triangle whose vertices are A(1/3,8/3), B(5/4, 1/4) and \n" ); document.write( "C(67,-13/6) \n" ); document.write( "------------- \n" ); document.write( " \r\n" ); document.write( " A B C A\r\n" ); document.write( " 1/3 5/4 67 1/3\r\n" ); document.write( " 8/3 1/4 -13/6 8/3\r\n" ); document.write( "\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Add the diagonal products starting upper left \n" ); document.write( "1/12 - 65/24 + 536/3 = 4225/24 \n" ); document.write( "--- \n" ); document.write( "Add the diagonal products starting lower left \n" ); document.write( "20/3 + 67/4 - 13/18 = 817/36 \n" ); document.write( "------------- \n" ); document.write( "Find the difference between the 2 sums. \n" ); document.write( "4225/24 - 817/36 = 11041/72 \n" ); document.write( "Area = 1/2 the difference \n" ); document.write( "Area = 11041/144 sq units \n" ); document.write( " \n" ); document.write( " |