document.write( "Question 1103173: find the area of the triangle whose vertices are (1/3,8/3), (5/4, 1/4)and (67,-13/6) \n" ); document.write( "
Algebra.Com's Answer #717861 by Alan3354(69443)\"\" \"About 
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find the area of the triangle whose vertices are A(1/3,8/3), B(5/4, 1/4) and
\n" ); document.write( "C(67,-13/6)
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document.write( "  A      B      C      A\r\n" );
document.write( " 1/3    5/4     67    1/3\r\n" );
document.write( " 8/3    1/4   -13/6   8/3\r\n" );
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\n" ); document.write( "\n" ); document.write( "Add the diagonal products starting upper left
\n" ); document.write( "1/12 - 65/24 + 536/3 = 4225/24
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\n" ); document.write( "Add the diagonal products starting lower left
\n" ); document.write( "20/3 + 67/4 - 13/18 = 817/36
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\n" ); document.write( "Find the difference between the 2 sums.
\n" ); document.write( "4225/24 - 817/36 = 11041/72
\n" ); document.write( "Area = 1/2 the difference
\n" ); document.write( "Area = 11041/144 sq units
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