document.write( "Question 98646: As a first year Algebra student, I am doing a little extra study and have run into a problem I can't solve.\r
\n" ); document.write( "\n" ); document.write( "Solve: [2x-5y] = [1] for y
\n" ); document.write( " [ x+3y] [0]\r
\n" ); document.write( "\n" ); document.write( "I tried to line them up - one under the other, but once I hit the submit button, it throws them out of alignment [x+3y]is directly under [2x-5y] and [0] is directly under [1]. Thank you. \n" ); document.write( "
Algebra.Com's Answer #71785 by malakumar_kos@yahoo.com(315)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( " Solve: [2x-5y] = [1] for y
\n" ); document.write( "[ x+3y] [0] \r
\n" ); document.write( "\n" ); document.write( " 2x-5y = 1...........(1)\r
\n" ); document.write( "\n" ); document.write( " x+3y = 0...........(2)\r
\n" ); document.write( "\n" ); document.write( " multiply (2) by 2 and subtract (1) and (3)\r
\n" ); document.write( "\n" ); document.write( " 2(x+3y) = 2(0)
\n" ); document.write( " 2x+6y = 0..........(3)\r
\n" ); document.write( "\n" ); document.write( " 2x-5y = 1
\n" ); document.write( " 2x+6y = 0
\n" ); document.write( " - -
\n" ); document.write( " ------------
\n" ); document.write( " 0 -11y = 1
\n" ); document.write( " ------------\r
\n" ); document.write( "\n" ); document.write( " y = -1/11\r
\n" ); document.write( "\n" ); document.write( " substituting for y in (2) we get x+3y = 0
\n" ); document.write( " x = -3y = -3(-1/11) = 3/11\r
\n" ); document.write( "\n" ); document.write( " the solution for the eq'ns is x= 3/11 and y = -1/11\r
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