document.write( "Question 98645: Find the measure of an angle whose supplement measures 38 degrees less than three times its complement. \n" ); document.write( "

Algebra.Com's Answer #71784 by malakumar_kos@yahoo.com(315) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( " Find the measure of an angle whose supplement measures 38 degrees less than three times its complement.\r
\n" ); document.write( "\n" ); document.write( " Let the required angle be x degrees\r
\n" ); document.write( "\n" ); document.write( " its supplement will be 180-x\r
\n" ); document.write( "\n" ); document.write( " its compliment will be 90-x\r
\n" ); document.write( "\n" ); document.write( " the relation given is supplement = 3(compliment)-38 degrees\r
\n" ); document.write( "\n" ); document.write( " 180-x = 3(90-x)-38\r
\n" ); document.write( "\n" ); document.write( " 3x-x = 270-180-38\r
\n" ); document.write( "\n" ); document.write( " 2x = 90-38 = 52\r
\n" ); document.write( "\n" ); document.write( " 2x = 52 or x = 52/2 = 26 degrees\r
\n" ); document.write( "\n" ); document.write( " the required angle = 26 degrees \n" ); document.write( "

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