document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=98619>Question 98619</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have tried but to no avail to solve the following problem:\r<BR>\n" );
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document.write( "Find the coordinates of the vertices of the figures formed by:\r<BR>\n" );
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document.write( "y&#8804;x+2, x+y&#8804;6, and y&#8805;-2. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #71783 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=71783\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> working with them as equalities makes things easier ... y=x+2, x+y=6, y=-2\r<BR>\n" );
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document.write( "the vertices with y=-2 are easiest, just substitute -2 into the other equations\r<BR>\n" );
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document.write( "-2=x+2 ... -4=x, so vertex is (-4,-2) ... x+(-2)=6 ... x=8, so vertex is (8,-2)\r<BR>\n" );
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document.write( "find the last vertex with a simultaneous solution\r<BR>\n" );
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document.write( "y=x+2 so x+(x+2)=6 ... 2x+2=6 ... x=2 ... y=2+2 ... y=4 ... vertex is (2,4) </SPAN>\n" );
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