document.write( "Question 1103116: I have this exponential equation that I cannot seem to solve:\r
\n" ); document.write( "\n" ); document.write( "5^x = 4^x+1\r
\n" ); document.write( "\n" ); document.write( "I didn't get very far; here's my lame attempt:\r
\n" ); document.write( "\n" ); document.write( "log5^x = log4^x+1
\n" ); document.write( "xlog5 = (x+1) log4\r
\n" ); document.write( "\n" ); document.write( "and that's about it. I don't know if I should distribute the log4 over the (x+1) or what. I know the answer is log4/log5/4 (\"log 4 divided by log 5/4\"), but I don't know how to get there. Can you help?
\n" ); document.write( "Thank you\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #717793 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "(Note that the given equation, as you show it, is 5^x = 4^x + 1, or \"5%5Ex+=+4%5Ex%2B1\"; that is much different than the equation you are really trying to solve, which is 5^x = 4^(x+1), or \"5%5Ex+=+4%5E%28x%2B1%29\". As another tutor on this site likes to say, \"parentheses are free -- use them!\")

\n" ); document.write( "You have done all you can do with the logarithms; now you have an equation in just x which you can solve.

\n" ); document.write( "Yes; distribute. Then solve for x (hint gather all the terms with x on one side of the equation).

\n" ); document.write( "Then note that the given answer, \"log%284%29%2Flog%285%2F4%29\", can be written, using laws of logarithms, as \"log%284%29%2F%28log%285%29-log%284%29%29\".

\n" ); document.write( "When you finish solving your equation for x, that is exactly what you should get.
\n" ); document.write( "
\n" );