document.write( "Question 1103117: Find the sum of the first 24 terms of the arithmetic series.
\n" ); document.write( "1+8+15+22+...
\n" ); document.write( "S(24)=
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Algebra.Com's Answer #717792 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "In ANY set of numbers, the sum of all the numbers is the average, multiplied by how many numbers there are.

\n" ); document.write( "In an arithmetic series, since the terms are \"evenly spaced\", the average of all the numbers is the average of the first and last terms.

\n" ); document.write( "So the sum of 24 terms of an arithmetic series is the average of the first and last terms, multiplied by 24.

\n" ); document.write( "The 24th term is the first term, plus the common difference added 23 times.

\n" ); document.write( "For this example, then...
\n" ); document.write( "The 24th term is \"1%2B23%2A7+=+1%2B161+=+162\"
\n" ); document.write( "The average of the first and last terms is \"%281%2B162%29%2F2+=+81.5\"
\n" ); document.write( "And the sum of the first 24 terms is \"81.5%2A24+=+1956\"

\n" ); document.write( "Note that many students prefer a different way of thinking of the sum of the terms of an arithmetic series. Instead of thinking
\n" ); document.write( "\"(average of first and last) times (the number of terms)\",
\n" ); document.write( "They group the numbers in pairs (1st term with 24th, 2nd with 23rd, and so on) so that each pair has the same sum; then they get the sum of all the terms in the series as
\n" ); document.write( "\"(sum of first and last terms) times (the number of pairs)\".

\n" ); document.write( "For your example, that method of thinking of the sum would give you...
\n" ); document.write( "There are 24 terms; so that is 12 pairs
\n" ); document.write( "The sum of the first and last terms is 1+162=163;
\n" ); document.write( "The sum of all the terms is 163*12 = 1956.
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