document.write( "Question 1103077: A positive integer is 11 less than another. If the sum of the reciprocal of the smaller and twice the reciprocal of the larger is 7/6, then find the two integers. \n" ); document.write( "
Algebra.Com's Answer #717775 by KMST(5328)\"\" \"About 
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THE FIFTH-GRADER APPROACH:
\n" ); document.write( "Let us try positive integers,
\n" ); document.write( "starting with \"1\" and \"1%2B11=12\" ,
\n" ); document.write( "and see if we bump into the solution.
\n" ); document.write( "The reciprocal are \"1%2F1=1\" and \"1%2F12\" ,
\n" ); document.write( "so the sum is
\n" ); document.write( "\"1%2B2%281%2F12%29=1%2B2%2F12=1%2B1%2F6=6%2F6%2B1%2F6=7%2F6\" ,
\n" ); document.write( "and that works, so if there is just one solution,
\n" ); document.write( "as the question suggests,
\n" ); document.write( "the numbers are \"highlight%281%29\" and \"highlight%2812%29\" .
\n" ); document.write( "
\n" ); document.write( "THE ALGEBRA STUDENT APPROACH:
\n" ); document.write( "\"x\"= the smaller positive integer
\n" ); document.write( "\"x%2B11\"= the larger positive integer
\n" ); document.write( "\"1%2Fx\"= the reciprocal of the smaller integer
\n" ); document.write( "\"2%281%2F%28x%2B11%29%29=2%2F%28x%2B11%29\"= twice the reciprocal of the larger integer
\n" ); document.write( "The sum is
\n" ); document.write( "\"1%2Fx%2B2%2F%28x%2B11%29=7%2F6\"
\n" ); document.write( "From here, we could say that
\n" ); document.write( "we multiply both sides of the equal sign times \"6x%28x%2B11%29\"
\n" ); document.write( "to eliminate denominators,
\n" ); document.write( "and get
\n" ); document.write( "\"6x%28x%2B11%29%281%2Fx%2B2%2F%28x%2B11%29%29=%287%2F6%29%2A%286x%28x%2B11%29%29\"
\n" ); document.write( "\"6x%28x%2B11%29%2Fx%2B2%2A6x%28x%2B11%29%2F%28x%2B11%29=7x%28x%2B11%29\"
\n" ); document.write( "\"6%28x%2B11%29%2B12x=7%28x%5E2%2B11x%29\"
\n" ); document.write( "\"6x%2B66%2B12x=7x%5E2%2B77x\"
\n" ); document.write( "\"18x%2B66=7x%5E2%2B77x\"
\n" ); document.write( "\"0=7x%5E2%2B77x-18x-66\"
\n" ); document.write( "\"7x%5E2%2B59x-66=0\"
\n" ); document.write( "At that point, knowing that x is a positive integer,
\n" ); document.write( "you know that factoring is an option.
\n" ); document.write( "Looking at the numbers, you see that \"x=1\" is a solution,
\n" ); document.write( "because \"7%2B59-66=66-66=0\" .
\n" ); document.write( "The factoring gives you
\n" ); document.write( "\"%28x-1%29%287x%2B66%29=0\" ,
\n" ); document.write( "and the positive inter solution is \"x=1\" , with \"x%2B11=1%2B11=12\" .
\n" ); document.write( "The other solution is \"x=-66%2F7\" , which is not a positive integer.
\n" ); document.write( "
\n" ); document.write( "You could instead think of finding a common denominator,
\n" ); document.write( "and calculating step by step:
\n" ); document.write( "\"%28x%2B11%29%2F%28x%28x%2B11%29%29%2B2x%2F%28%28%2B11%29%29=7%2F6\"
\n" ); document.write( "\"%28x%2B11%29%2F%28x%5E2%2B11x%29%2B2x%2F%28x%5E2%2B11x%29=7%2F6\"
\n" ); document.write( "\"%28x%2B11%2B2x%29%2F%28x%5E2%2B11x%29=7%2F6\"
\n" ); document.write( "\"%283x%2B11%29%2F%28x%5E2%2B11x%29=7%2F6\"
\n" ); document.write( "\"6%283x%2B11%29%2F%28x%5E2%2B11x%29=7\"
\n" ); document.write( "\"6%283x%2B11%29=7%28x%5E2%2B11x%29\"
\n" ); document.write( "\"18x%2B66=7x%5E2%2B77x\"
\n" ); document.write( "Same result, just not as elegant.
\n" ); document.write( "
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