document.write( "Question 1103023: Why wouldnt i use order of operations in this equation? If i did the answer would be x=1 yet its 4 because the addition was applied first??
\n" ); document.write( "Solve for x when y is equal to 0.
\n" ); document.write( "y = 1/4x - 1
\n" ); document.write( "0 = 1/4x - 1
\n" ); document.write( "0 + 1 = 1/4x - 1 + 1
\n" ); document.write( "1 = 1/4x
\n" ); document.write( "4 • (1) = (1/4x) • 4
\n" ); document.write( "4 = x?
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\n" ); document.write( "AL SAYS:
\n" ); document.write( "Not clear why you have a question.
\n" ); document.write( "y = (1/4)x - 1 = 0
\n" ); document.write( "(1/4)x - 1 = 0
\n" ); document.write( "(1/4)x =1
\n" ); document.write( "x = 4\r
\n" ); document.write( "\n" ); document.write( "BUT i still am confused he just stated the same problem i asked, i am confused on why the addition of one on both sides is done BEFORE the multiplication of 4 on both sides, PEMDAS or aka order of ops says multilpication b4 addition.... PLZ HELP ME!!!(: \n" ); document.write( "
Algebra.Com's Answer #717727 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
PEMDAS makes no difference in the problem.
\n" ); document.write( "Either way, x = 4
\n" ); document.write( "==============
\n" ); document.write( "(1/4)x - 1 = 0
\n" ); document.write( "Multiply by 4
\n" ); document.write( "x - 4 = 0
\n" ); document.write( "x = 4
\n" ); document.write( " \n" ); document.write( "
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