document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1103000>Question 1103000</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve using the substitution method<BR>\n" );
document.write( "x=8y-3<BR>\n" );
document.write( "x=2y-9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #717706 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=717706\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1) x = 8y - 3<BR>\n" );
document.write( "2) x = 2y - 9<BR>\n" );
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document.write( "use equation 1) and substitute for x in equation 2)<BR>\n" );
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document.write( "8y - 3 = 2y - 9<BR>\n" );
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document.write( "subtract 2y from both sides of =<BR>\n" );
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document.write( "6y - 3 = -9<BR>\n" );
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document.write( "add 3 to boh sides of = <BR>\n" );
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document.write( "6y = -6<BR>\n" );
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document.write( "divide both sides of = by 6<BR>\n" );
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document.write( "y = -1<BR>\n" );
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document.write( "we can use either equation 1 or 2 and substitute for y<BR>\n" );
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document.write( "use equation 1)<BR>\n" );
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document.write( "x = 8(-1) -3<BR>\n" );
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document.write( "x = -11<BR>\n" );
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document.write( "x = -11 and y = -1<BR>\n" );
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document.write( "check our answer<BR>\n" );
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document.write( "equation 1<BR>\n" );
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document.write( "-11 = 8(-1) -3<BR>\n" );
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document.write( "-11 = -11<BR>\n" );
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document.write( "equation 2<BR>\n" );
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document.write( "-11 = 2(-1) -9<BR>\n" );
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document.write( "-11 = -11<BR>\n" );
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document.write( "our answers check for equations 1 and 2<BR>\n" );
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document.write( "  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );