document.write( "Question 1102976: Gabriela had a snack of 7 carrots and 9 Hershey kisses for 355 calories. Ciarra had 5 carrots and 12 Hershey kisses for 265 calories. How many calories are in one carrot? How many calories are in one Hershey kiss? \n" ); document.write( "
Algebra.Com's Answer #717690 by ankor@dixie-net.com(22740)\"\" \"About 
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Gabriela had a snack of 7 carrots and 9 Hershey kisses for 355 calories.
\n" ); document.write( " Ciarra had 5 carrots and 12 Hershey kisses for 265 calories.
\n" ); document.write( " How many calories are in one carrot? How many calories are in one Hershey kiss?
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\n" ); document.write( "let h = no. of calories in a Hershey kiss
\n" ); document.write( "let c = no. of calories in a carrot
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\n" ); document.write( "write an equation for each statement
\n" ); document.write( "\"Gabriela had a snack of 7 carrots and 9 Hershey kisses for 355 calories.
\n" ); document.write( "7c + 9h = 355
\n" ); document.write( "\"Ciarra had 5 carrots and 12 Hershey kisses for 265 calories.\"
\n" ); document.write( "5c + 12h = 265
\n" ); document.write( "we will use elimination here, multiply the 1st equation by 5, the 2nd by 7
\n" ); document.write( "35c + 45h = 1775
\n" ); document.write( "35c + 84h = 1855
\n" ); document.write( "for subtraction it is better to rearrange it:
\n" ); document.write( "35c + 84h = 1855
\n" ); document.write( "35c + 45h = 1775
\n" ); document.write( "------------------subtraction eliminates c, find h
\n" ); document.write( "0 + 39h = 80
\n" ); document.write( "h = 80/39
\n" ); document.write( "h = 2.0513 ~ 2 calories per kiss
\n" ); document.write( ":
\n" ); document.write( "Use the first equation to find the no. of calories in the carrot
\n" ); document.write( "7c + 9(2) = 355
\n" ); document.write( "7c = 355 - 18
\n" ); document.write( "7c = 337
\n" ); document.write( "c = 337/7
\n" ); document.write( "c = 48.143 ~ 48 calories per carrot
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\n" ); document.write( "Check these solutions in the 2nd equation
\n" ); document.write( "5(48) + 12(2) = 265
\n" ); document.write( "240 + 24 = 264, close enough \r
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