document.write( "Question 1102961: I have this problem: 4log(base6)x=log(base6)64. My answer was x=64^1/4. I was hesitant to go with this answer because my textbook had no examples that ended in an answer like that. Is this correct? If not, how do I solve this correctly? Thanks!1/4 \n" ); document.write( "
Algebra.Com's Answer #717680 by greenestamps(13215)\"\" \"About 
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\n" ); document.write( "Solving the equation is rather easy, since we have log base 6 on both sides.

\n" ); document.write( "We get \"x%5E4=64\", so your answer \"64%5E%281%2F4%29\" is valid.

\n" ); document.write( "However, it can be simplified in many ways, without resorting to an irrational approximation obtained with a calculator.

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\n" ); document.write( "All of those forms are equivalent. In most situations either \"2%5E%283%2F2%29\" or \"2%2Asqrt%282%29\" would be considered the best forms.
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