document.write( "Question 1102971: Marge invests $7,000 , part at 6% and part at 9%. If she ears $493 interest how much is invested in each account.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #717667 by addingup(3677)\"\" \"About 
You can put this solution on YOUR website!
Of a total of 7000 she invests x money at 6%. And the rest, 7000 - x, she invests at 9%
\n" ); document.write( "------------------------
\n" ); document.write( "0.06x + 0.09(7000 - x) = 493
\n" ); document.write( "0.06x + 630 - 0.09x = 493
\n" ); document.write( "-0.03x = -137
\n" ); document.write( "x = 4566.67 this is the amount invested at 6x. The amount invested at 9% is 7000-4566.67 = 2433.33
\n" ); document.write( "
\n" );