document.write( "Question 1102971: Marge invests $7,000 , part at 6% and part at 9%. If she ears $493 interest how much is invested in each account.
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Algebra.Com's Answer #717664 by ikleyn(52933) $\"\"$ $\"About$

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document.write( "0.06*x + 0.09*(7000-x) = 493.\r\n" );
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document.write( "Solve for x.\r\n" );
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document.write( "6x + 9*(7000-x) = 49300\r\n" );
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document.write( "6x + 63000 - 9x = 49300  ====>  -3x = 49300 - 63000 = -13700  ====>  x =  = 4566.67 dollars invested at 6%.\r\n" );
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document.write( "The rest, 7000 - 4566.67 = 2433.33 dollars invested at 9%.\r\n" );
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