document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1102925>Question 1102925</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ref. Question 1102916:\r<BR>\n" );
document.write( "\n" );
document.write( "Question re-worded;\r<BR>\n" );
document.write( "\n" );
document.write( "The wheels of a carriage take one more second to revolve, resulting in the rate per hr. being 2 2/3 miles less.  Determine rate. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #717660 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=717660\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The wheels of a carriage take one more second to revolve, resulting in the rate per hr. being 2 2/3 miles less.<BR>\n" );
document.write( " Determine rate. <BR>\n" );
document.write( ":<BR>\n" );
document.write( "let r = original rate in mph<BR>\n" );
document.write( "then using the decimal equiv of 2/3<BR>\n" );
document.write( "(r - 2.6667) = the slower rate in mph<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Assuming the revolutions in rpm:<BR>\n" );
document.write( " original rev takes 60 sec,<BR>\n" );
document.write( " slower rev take 61 sec<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Using an inverse relationship, (faster speed means less time)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r%2F%28%28r-2.6667%29%29 ALIGN=MIDDLE  ALT=\"r%2F%28%28r-2.6667%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=61%2F60 ALIGN=MIDDLE  ALT=\"61%2F60\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Cross multiply<BR>\n" );
document.write( "60r = 61(r-2.6667)<BR>\n" );
document.write( "60r = 61r - 162<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2F3 ALIGN=MIDDLE  ALT=\"2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "60r - 61r = -162<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2F3 ALIGN=MIDDLE  ALT=\"2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "-r = -162<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2F3 ALIGN=MIDDLE  ALT=\"2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "r = 162<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2F3 ALIGN=MIDDLE  ALT=\"2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > mph is the original speed ant<BR>\n" );
document.write( "162<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2F3 ALIGN=MIDDLE  ALT=\"2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >- 2<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2F3 ALIGN=MIDDLE  ALT=\"2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 160 mph is the slower speed<BR>\n" );
document.write( ":<BR>\n" );
document.write( ";<BR>\n" );
document.write( "Not sure if I interpreted this correctly. Let me know please, ankor@att.net </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );