document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=98622>Question 98622</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have another problem with solving for x that I could use some help with please.  \r<BR>\n" );
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document.write( "5/x+6 + 2/x^2+7x+6 = 3/x+1\r<BR>\n" );
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document.write( "I am pretty sure I do not have this answer correct Thanks for your help.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #71765 by </B><A HREF=/tutors/aboutme.mpl?userid=malakumar_kos@yahoo.com><B>malakumar_kos@yahoo.com(315)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=malakumar_kos@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=71765\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">         \r<BR>\n" );
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document.write( "         5/x+6 + 2/x^2+7x+6 = 3/x+1<BR>\n" );
document.write( "               factorising x^2+7x+6 we get (x+6)& (x+1)<BR>\n" );
document.write( "             taking L.C.M for (x+6) (x+1) & (x+6)  we get (x+6)&(x+1)\r<BR>\n" );
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document.write( "           [5(x+1)+2]/(x+6)(x+1) = 3/(x+1)<BR>\n" );
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document.write( "           5x+5+2/(x+6) = 3  [cancelling (x+1) on both sides]\r<BR>\n" );
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document.write( "           5x+7 = 3(x+6)\r<BR>\n" );
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document.write( "           5x+7-3x-18 = 0\r<BR>\n" );
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document.write( "              2x-11 = 0\r<BR>\n" );
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document.write( "                 2x = 11<BR>\n" );
document.write( "                  x = 11/2 </SPAN>\n" );
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