document.write( "Question 1102897: A twin-engine plane flies 540 mi in the same amount of time it takes a single-engine plane to fly 360 mi. The rate of the twin-engine plane is 60 mph faster than the rate of the single-engine plane. Find the rate of the twin-engine plane. \n" ); document.write( "

Algebra.Com's Answer #717611 by greenestamps(13215) $\"\"$ $\"About$

You can put this solution on YOUR website!

\n" ); document.write( "The other tutor's answer is perfectly good; here is another way to solve the problem that I personally think is easier....

\n" ); document.write( "The time is the same for the two planes, so the ratio of the speeds will be the same as the ratio of the distances covered.
\n" ); document.write( "The ratio of the distances covered is 540:360 = 3:2, so the ratio of the speeds is 3:2.

\n" ); document.write( "With the ratio of speeds being 3:2, represent them with 3x and 2x. Then, since the difference in speeds is 60mph,
\n" ); document.write( " $\"3x-2x+=+60\"$
\n" ); document.write( " $\"x+=+60\"$
\n" ); document.write( "The speeds of the two planes are 3x=120mph and 2x=120mph. \n" ); document.write( "

\n" );