document.write( "Question 1102721: please help me answer these questions.\r
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document.write( "1. For a certain urban area, it was found that in a sample of 6 months, an average of 31 burglaries occurred each month. The standard deviation was 4. find the 90% confidence interval of the true mean number of burglaries each month.\r
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document.write( "2. A sample of 20 tuna showed that they swim an average of 8.6 miles per hour. The standard deviation for the sample was 1.6. find the 95% confidence interval of the true mean. \n" );
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Algebra.Com's Answer #717598 by Boreal(15235) You can put this solution on YOUR website! CI is mean +/- t (df, value)*s/sqrt(n) \n" ); document.write( "for the first, it is 31 +/- t(df=31,0.95)*4/sqrt(31) \n" ); document.write( "This is 31 +/- (1.70*4/sqrt(31)) \n" ); document.write( "That is 31+/-1.22 \n" ); document.write( "(29.78, 32.22) burglaries \n" ); document.write( "======================= \n" ); document.write( "second is done same way \n" ); document.write( "CI is 8.6 +/-2.093*1.6/sqrt(20) \n" ); document.write( "=8.6+/-0.75 \n" ); document.write( "(7.85, 9.35) speed in mph\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |