document.write( "Question 1102883: How many terms must be added in an arithmetic sequence whose first term is 1919 and whose common difference is 66 to obtain a sum of 4012​? \n" ); document.write( "
Algebra.Com's Answer #717587 by josgarithmetic(39618)\"\" \"About 
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First term, 1919
\n" ); document.write( "Last term, 1919+66(n-1) for index n\r
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\n" ); document.write( "\n" ); document.write( "The given sum 4012,\r
\n" ); document.write( "\n" ); document.write( "\"%28n%2F2%29%281919%2B1919%2B66%28n-1%29%29=4012\"
\n" ); document.write( "Simplify and solve.
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