document.write( "Question 1102792: Find three consecutive even integers such that the square of the first is 80 less than the square of the third. (Only an algebraic solution will be accepted. ) \n" ); document.write( "
Algebra.Com's Answer #717531 by ikleyn(52782)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "Let n be the central of these tree consecutive integers, so that the numbers are\r\n" ); document.write( "\r\n" ); document.write( "n-2, n and n+2.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Then the condition says\r\n" ); document.write( "\r\n" ); document.write( "(n+2)^2 - (n-2)^2 = 80, or, expanding parentheses,\r\n" ); document.write( "\r\n" ); document.write( "n^2 + 4n + 4 - (n^2 -4n +4) = 80,\r\n" ); document.write( "\r\n" ); document.write( "which is simplified to\r\n" ); document.write( "\r\n" ); document.write( "8n = 80.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Hence, n =\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |