document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1102486>Question 1102486</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A previous survey shows that a machine making plastic components is correctly set up for the day's production on 95% of days. On days when it is set up correctly, 98% of the components produced are good. If the machine is not set up correctly, only 40% of the components produced are good. On a particular day, the machine is set up and the first component produced is found to be good. What is the probability that the machine is set up correctly? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #717497 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=717497\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P(MG|PGood)=P(PGood|MG)*P(MG)/P(Part good|MG)*P(MG)+P(Part good)|MN)*P(MN)<BR>\n" );
document.write( "This is 0.98*0.95/(0.98*0.95)+(0.4)*(0.05)=0.931/0.953=0.977 or 97.7% </SPAN>\n" );
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